Compromise Solution In Economic Competition
Table 3: Values of winnings for distribution participants
Xi | Agent 1 | Agent 2 | Agent 3 |
1 | H1(x1) = 2 | H2(x1) = 7 | H3(x1) = 9 |
2 | H1(x2) = 2 | H2(x2) = 2 | H3(x2) = 2 |
3 | H1(x3) = 6 | H2(x3) = 2 | H3(x3) = 7 |
4 | H1(x4) = 7 | H2(x4) = 7 | H3(x4) = 7 |
5 | H1(x5) = 7 | H2(x5) = 1 | H3(x5) = 2 |
6 | H1(x6) = 6 | H2(x6) = 1 | H3(x6) = 9 |
Let us find for each column an element of the ideal vector M (maximum value): M1 = 7, M2 = 7, M3 = 9 M = (7, 7, 9). Let's calculate the deviation values . |